x^2+xy+4y^2=0

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Solution for x^2+xy+4y^2=0 equation:


Simplifying
x2 + xy + 4y2 = 0

Reorder the terms:
xy + x2 + 4y2 = 0

Solving
xy + x2 + 4y2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-4y2' to each side of the equation.
xy + x2 + 4y2 + -4y2 = 0 + -4y2

Combine like terms: 4y2 + -4y2 = 0
xy + x2 + 0 = 0 + -4y2
xy + x2 = 0 + -4y2
Remove the zero:
xy + x2 = -4y2

The x term is xy.  Take half its coefficient (0.5y).
Square it (0.25y2) and add it to both sides.

Add '0.25y2' to each side of the equation.
xy + x2 + 0.25y2 = -4y2 + 0.25y2

Combine like terms: -4y2 + 0.25y2 = -3.75y2
xy + x2 + 0.25y2 = -3.75y2

Factor a perfect square on the left side:
(x + 0.5y)(x + 0.5y) = -3.75y2

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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